Primary Memory: RAM, ROM and Cache
A heavy nucleus packed with too many protons and neutrons is not at peace. It will, sooner or later, spit out a particle or a photon to settle into something more stable — and you cannot speed it up by heating it, cool it down to stop it, or push it with pressure. This unstoppable internal "settling" is what we call radioactivity, and JEE Main loves it because it ties nuclear physics, exponential mathematics and conservation laws into one tidy package.
Definition: Radioactivity is the spontaneous disintegration of unstable atomic nuclei accompanied by the emission of alpha (α), beta (β) or gamma (γ) radiation. The phenomenon was discovered by Henri Becquerel in 1896 and explored deeply by Marie and Pierre Curie.
The Three Kinds of Decay
Alpha (α) Decay
Definition: An alpha particle is a helium-4 nucleus — two protons and two neutrons — ejected as a single bound unit. So when a nucleus undergoes α-decay, its mass number A drops by 4 and its atomic number Z drops by 2.
General equation:ᴬZX → ᴬ⁻⁴Z₋₂Y + ⁴₂He
Example: ²³⁸₉₂U → ²³⁴₉₀Th + ⁴₂He.
Alpha particles are heavy and doubly charged. They lose energy quickly as they smash through matter, so they have very low penetration but very high ionizing power — a sheet of paper stops them, but inside the body (if inhaled) they cause heavy damage.
Beta-Minus (β⁻) Decay
Inside a neutron-rich nucleus, one neutron converts into a proton, emitting an electron (the β⁻ particle) and an electron antineutrino:n → p + e⁻ + ν̄ₑ
So Z increases by 1, A is unchanged.
General equation:ᴬZX → ᴬZ₊₁Y + e⁻ + ν̄ₑ
Example: ¹⁴₆C → ¹⁴₇N + e⁻ + ν̄ₑ. (This is the decay behind carbon-14 dating.)
Beta-Plus (β⁺) Decay
In a proton-rich nucleus, a proton converts into a neutron, emitting a positron (the β⁺ particle) and an electron neutrino:p → n + e⁺ + νₑ
So Z decreases by 1, A is unchanged.
General equation:ᴬZX → ᴬZ₋₁Y + e⁺ + νₑ
Example: ²²₁₁Na → ²²₁₀Ne + e⁺ + νₑ.
Gamma (γ) Decay
After α or β decay, the daughter nucleus is often left in an excited state. It releases the extra energy as a high-energy photon — a γ-ray. No change in A or Z; only the internal energy of the nucleus drops.
ᴬZX* → ᴬZX + γ
Penetration vs. Ionization — Two Inverted Rankings
These two rankings are routinely confused, so memorise them as a mirror pair.
- Penetration power: γ > β > α (γ punches through metres of concrete, β through aluminium, α stops at paper).
- Ionizing power: α > β > γ (α leaves the densest trail of ion pairs because of its high charge and mass and low speed).
Why opposite? A particle that ionizes heavily loses energy at every step and therefore cannot penetrate far. A particle that ionizes lightly slips through matter and travels far.
The Law of Radioactive Decay
Definition: The law of radioactive decay states that the rate of disintegration at any instant is directly proportional to the number of undecayed nuclei present at that instant.
Mathematically:dN/dt = −λN
where N is the number of undecayed nuclei at time t and λ (the decay constant) is the probability per unit time that any individual nucleus decays. The minus sign just says N is decreasing.
Separating variables and integrating from N = N₀ at t = 0:
N = N₀ e^(−λt)
This exponential is the heart of the chapter. It says the population of undecayed nuclei falls off exponentially with a characteristic time scale set by λ.
Activity
Definition: The activity A of a radioactive sample is the number of decays per second:A = λN = A₀ e^(−λt)
Units:
- 1 becquerel (Bq) = 1 decay per second (SI unit).
- 1 curie (Ci) =
3.7 × 10¹⁰Bq (the older, larger practical unit).
Half-Life and Mean Life
Two derived constants you will use constantly:
- Half-life
T₁/₂ = (ln 2) / λ ≈ 0.693 / λ. After every half-life, the remaining undecayed nuclei halve. - Mean (average) life
τ = 1 / λ. SoT₁/₂ = τ · ln 2, i.e. half-life is about 69.3% of the mean life.
After n half-lives, fraction surviving = (1/2)ⁿ.
Why It Matters
The exponential law is the universal mathematics of radioactivity — it works equally well for a tiny medical tracer in your bloodstream, for carbon-14 in a 5000-year-old fossil, and for spent uranium in a nuclear waste cask buried for centuries. It also gives us the tool to date things (from ancient artifacts to rocks billions of years old) and to dose medical treatments (the amount of tracer left in the patient at any time is a simple exponential calculation).
Real-world example: In Indian hospitals such as AIIMS and Tata Memorial, technetium-99m is the workhorse of nuclear medicine imaging. It has a half-life of about 6 hours — short enough that the patient's body is essentially clear of activity by the next day, but long enough that imaging is comfortable. The decay law N = N₀ e^(−λt) directly tells the radiologist how much activity remains at the time of the scan, given the dose at injection.
Common misconception: Many students think radioactive decay can be slowed down by cooling or pressurising the sample. It cannot. Radioactive decay is an internal nuclear process — temperature, pressure, chemical state and electromagnetic environment have no effect on λ (to extraordinary precision). This is one of the reasons radiometric dating is so trustworthy.
Another common slip: writing β-decay without the (anti)neutrino. JEE Main rarely penalises for that, but advanced/qualifying conceptual questions expect you to know that both β⁻ and β⁺ are three-body decays — energy and momentum conservation in β-decay was historically what predicted the neutrino.
A Worked Example
Question: A radioactive sample has a half-life of 10 minutes. If the initial activity is 8 × 10⁴ Bq, what is the activity after 30 minutes?
Solution:
Step 1: Number of half-lives elapsed: n = 30 / 10 = 3.
Step 2: Surviving fraction = (1/2)³ = 1/8.
Step 3: New activity = initial activity × surviving fraction = 8 × 10⁴ × (1/8) Bq.
Conclusion: Activity after 30 minutes = 1 × 10⁴ Bq.
Conservation Laws While Balancing Decay Equations
For every decay equation, two conservations must hold:
- Mass number (A) conservation: sum of A on the left = sum on the right.
- Atomic number (Z) conservation: sum of Z on the left = sum on the right (treat the electron as Z = −1 and the positron as Z = +1).
These two checks catch almost every algebraic mistake. Use them every time.
| Property | Alpha (α) | Beta-minus (β⁻) | Beta-plus (β⁺) | Gamma (γ) |
|---|---|---|---|---|
| Nature | ⁴₂He nucleus | Electron | Positron | Photon |
| Change in A | −4 | 0 | 0 | 0 |
| Change in Z | −2 | +1 | −1 | 0 |
| Charge | +2e | −e | +e | 0 |
| Penetration | Very low | Moderate | Moderate | Very high |
| Ionization | Very high | Moderate | Moderate | Very low |
| Stopped by | Paper | Aluminium foil | Aluminium foil | Lead / thick concrete |
- ✓- Radioactivity is spontaneous; rate is independent of temperature, pressure or chemistry.
- ✓- α decay: A → A−4, Z → Z−2; β⁻: Z → Z+1; β⁺: Z → Z−1; γ: no A or Z change.
- ✓- Decay law:
N = N₀ e^(−λt); activityA = λN. - ✓-
T₁/₂ = 0.693/λ; mean lifeτ = 1/λ; afternhalf-lives,(1/2)ⁿsurvives. - ✓- Penetration order γ > β > α; ionization order α > β > γ — exact opposites.
- ✓- Always balance A and Z when writing decay equations.
- ✓- 1 Bq = 1 decay/s; 1 Ci =
3.7 × 10¹⁰Bq.
"GBA up, ABG down" — for penetration, gamma > beta > alpha; for ionization, alpha > beta > gamma. Same three particles, opposite rankings.
- ✓- Three decay modes (α, β, γ) shift A and Z in fixed, predictable ways.
- ✓- Exponential decay law
N = N₀ e^(−λt)governs every radioactive sample. - ✓- Half-life and mean life are two different ways of describing the same
λ. - ✓- Conservation of A and Z lets you balance any decay equation in seconds.
Units of Memory and Conversion
Memory is measured in bits and bytes. 1 Byte = 8 bits. The ascending order:
Bit < Nibble (4 bits) < Byte (8 bits) < KB < MB < GB < TB < PB < EB < ZB < YB.
1 KB = 1024 bytes (2^10)
1 MB = 1024 KB (2^20)
1 GB = 1024 MB (2^30)
1 TB = 1024 GB (2^40)
1 PB = 1024 TB (2^50)
Memory aid for the ladder: 'Kilo Mega Giga Tera Peta Exa Zetta Yotta' = 'Kind Men Give Tea Para Even Zebra Yearly'. Note: in marketing, manufacturers often use powers of 10 (1 KB = 1000 bytes), but for exam binary calculations use 1024. A nibble = half a byte = 4 bits is a favourite trick question.
Worked Example: How Many Files Fit on a Disk
Bank PO papers love to dress up plain arithmetic in a "computer" costume. A song, a pen drive, a file size — the question is really just division, but you only spot that if you trust the units.
Definition: A byte is the basic unit of digital storage; a kilobyte (KB), megabyte (MB) and gigabyte (GB) are powers of 1024 in the binary system (1 KB = 1024 B, 1 MB = 1024 KB, 1 GB = 1024 MB).
Definition: Storage capacity of a device is the total number of bytes it can hold; the number of files it can store equals total capacity divided by the size of one file (assuming uniform files and no overheads).
The worked example
Question: How many songs of 4 MB each can be stored on a 2 GB pen drive (use 1 GB = 1024 MB)?
Solution:
Step 1: Convert 2 GB to MB so both numbers are in the same unit: 2 × 1024 = 2048 MB.
Step 2: Divide the total capacity by the file size: 2048 ÷ 4 = 512.
Conclusion: The pen drive holds 512 songs.
That is the entire computation. The discipline is to write the units next to every number — "2048 MB ÷ 4 MB = 512" — so the unit cancellation reminds you that the answer is a pure count, not a megabyte figure.
The exponent shortcut
Bank PO is a speed exam. If you spot powers of two, ditch long division. 2 GB = 2 × 2^10 MB = 2^11 MB. The file size 4 MB = 2^2 MB. Then 2^11 ÷ 2^2 = 2^(11−2) = 2^9 = 512. Three lines, no carrying, no calculator. The same trick demolishes "How many 256 KB photos fit on a 64 MB chip?" — 64 MB = 2^6 × 2^10 KB = 2^16 KB; 256 KB = 2^8 KB; answer = 2^8 = 256 photos. Once you train your eye to read storage sizes as powers of two, these questions take less than 20 seconds.
Why it matters
In IBPS PO and Clerk Mains, Computer Awareness gives 20 free marks if you've drilled three patterns: unit conversion, hierarchy of memory (cache → RAM → SSD → HDD), and abbreviations. "How many files fit" is the workhorse arithmetic version. Examiners hide it inside a Data Interpretation set — a paragraph about a school computer lab buying USB drives — and weak candidates miss the cue. Strong candidates spot "÷ file size" the moment they see two storage figures in the same problem.
Real-world example
Think of your own phone. A standard MP3 song at 192 kbps for three minutes is roughly 4 MB. A 32 GB SD card holds 32 × 1024 ÷ 4 = 8192 songs in theory, though the operating system, album art and metadata eat a few hundred megabytes. The PO question deliberately ignores those overheads — it is testing your arithmetic, not your audiophile knowledge.
Common misconception
Aspirants often use 1 GB = 1000 MB (decimal SI prefix) instead of the binary 1024 MB. Pen-drive manufacturers print decimal capacities on the box (which is why a "32 GB" drive shows ~29.8 GB in Windows), but Indian bank exams always want the binary value unless the problem explicitly says otherwise. Read the line "use 1 GB = 1024 MB" as a gift, not a hint — it removes ambiguity.
A second misconception: dividing the wrong way around. If the question is "how many 4 MB files fit in 2 GB," the file size goes in the denominator. Some students panic and compute 4 ÷ 2048, getting a fraction. Sanity check: the answer should be much bigger than 1 if the device is bigger than one file.
Variation: when the file size is uneven
Question: A pen drive of 8 GB stores 1000 photos of 5 MB each and the rest are 2 MB songs. How many songs?
Solution:
Step 1: Total capacity = 8 × 1024 = 8192 MB.
Step 2: Photo space = 1000 × 5 = 5000 MB.
Step 3: Remaining space = 8192 − 5000 = 3192 MB.
Step 4: Songs = 3192 ÷ 2 = 1596.
Conclusion: 1596 songs fit in the remaining space.
The technique is the same: stay in one unit, treat each subcalculation in MB, and finish with a single division.
| Unit | Decimal value | Binary value | Bank PO expects |
|---|---|---|---|
| 1 KB | 1000 B | 1024 B | 1024 B |
| 1 MB | 1000 KB | 1024 KB | 1024 KB |
| 1 GB | 1000 MB | 1024 MB | 1024 MB |
| 1 TB | 1000 GB | 1024 GB | 1024 GB |
- ✓- Number of files = total capacity ÷ size per file, with both sides in the same unit.
- ✓- Convert GB to MB (multiply by 1024) before dividing, unless the file is in GB.
- ✓- 1024 = 2^10, so storage problems often reduce to exponent subtraction.
- ✓- Bank PO uses binary (1024) by default; the question will say so if decimal is wanted.
- ✓- Sanity check: if device size ≫ file size, expect a large integer answer.
- ✓- For mixed-content drives, subtract used space first, then divide.
- ✓- "÷ file size" is the structural clue hidden inside DI word problems.
"Same unit, then divide." Before any storage division, ask: are both numbers in MB? In KB? Only then is the slash safe.
- ✓- Memory units are powers of 1024 in Indian bank exams.
- ✓- Convert to a common unit, then divide capacity by file size.
- ✓- Use 2^n arithmetic to dodge long division.
- ✓- The structural trigger inside a DI set is the phrase "÷ file size."
Memory & Storage Hierarchy — revision notes (IBPS PO)
Memory is the single highest-yield computer topic in IBPS PO — RAM vs ROM, volatile vs non-volatile, memory units and the hierarchy appear almost every year (2–3 questions). Memorise the units and the RAM/ROM split cold.
The memory hierarchy (top = fastest, costliest, smallest)
Registers → Cache (L1 > L2 > L3) → Primary/Main memory (RAM) → Secondary (HDD/SSD) → Tertiary (tape).
Going DOWN: speed decreases, capacity increases, cost-per-byte decreases.
Primary memory
- RAM (Random Access Memory): volatile (loses data on power-off), read/write, main working memory.
- SRAM (Static): faster, uses flip-flops, no refresh needed, used in cache.
- DRAM (Dynamic): cheaper, uses capacitors, needs constant refresh, used as main memory.
- ROM (Read Only Memory): non-volatile, stores boot firmware (BIOS).
- PROM (programmed once), EPROM (erased by UV light), EEPROM (erased electrically).
- Cache memory: very fast buffer between CPU and RAM; L1 closest/fastest.
- Virtual memory: uses part of secondary storage (disk) as extra RAM.
Memory units (learn the ladder)
| Unit | Size |
|---|---|
| 1 Nibble | 4 bits |
| 1 Byte | 8 bits |
| 1 KB | 1024 Bytes (2¹⁰) |
| 1 MB | 1024 KB |
| 1 GB | 1024 MB |
| 1 TB | 1024 GB |
| Then | PB → EB → ZB → YB |
Secondary storage
- Magnetic: HDD, magnetic tape (sequential access).
- Optical: CD ≈ 700 MB, DVD ≈ 4.7 GB, Blu-ray ≈ 25 GB.
- Solid-state: SSD, USB pen drive, memory card — flash memory, no moving parts, faster than HDD.
Exam Tricks & Tips
- 🎯 RAM = volatile (temporary), ROM = non-volatile (permanent). Mnemonic: "RAM = Removed on shutdown".
- 🎯 Order KMGTP = KB, MB, GB, TB, PB (each ×1024). Smallest = bit → nibble (4) → byte (8).
- 🎯 EPROM = Erased by Ultraviolet (UV) light; EEPROM = Electrically erased.
- 🎯 SRAM = cache (Static, fast), DRAM = main memory (Dynamic, needs refresh).
- 🎯 Cache is faster than RAM but smaller; registers are faster than cache.
- ❌ Common mistake: thinking ROM is volatile — it is NON-volatile; RAM is the volatile one.
Expected exam pattern
"1 byte = ? bits", "Which memory is volatile?", "BIOS is stored in ?", "EPROM is erased by ?", "Cache is between CPU and ?". All 1-line recall.
Quick recap
Hierarchy: Register > Cache > RAM > HDD/SSD > Tape. RAM volatile, ROM non-volatile. Byte = 8 bits, KB = 1024 B. SRAM→cache, DRAM→main. Optical sizes: CD 700MB, DVD 4.7GB, Blu-ray 25GB.
Memory & Storage Hierarchy — Flashcards (IBPS PO)
Cover the answer, recall, then check. 12 cards on memory types, units and storage.
Q1. Which is volatile: RAM or ROM?
A1. RAM is volatile (loses data on power-off). ROM is non-volatile (retains data).
Q2. How many bits are in 1 byte, and in 1 nibble?
A2. 1 byte = 8 bits; 1 nibble = 4 bits.
Q3. How many bytes are in 1 KB?
A3. 1024 bytes (2¹⁰).
Q4. Difference between SRAM and DRAM?
A4. SRAM is static, faster, uses flip-flops, needs no refresh (used in cache). DRAM is dynamic, cheaper, uses capacitors, needs refresh (used as main memory).
Q5. How is EPROM erased?
A5. By exposure to ultraviolet (UV) light. (EEPROM is erased electrically.)
Q6. Where is the BIOS / boot firmware stored?
A6. In ROM (non-volatile memory).
Q7. Order the memory hierarchy from fastest to slowest.
A7. Registers > Cache > Primary memory (RAM) > Secondary (HDD/SSD) > Tertiary (tape).
Q8. What is cache memory?
A8. A small, very fast memory between the CPU and RAM that stores frequently used data; L1 is closest and fastest.
Q9. Approximate storage of CD, DVD and Blu-ray discs?
A9. CD ≈ 700 MB, DVD ≈ 4.7 GB, Blu-ray ≈ 25 GB.
Q10. What is virtual memory?
A10. A technique using part of the secondary storage (disk) as an extension of RAM when physical RAM is insufficient.
Q11. Arrange units in ascending order: GB, KB, TB, MB, PB.
A11. KB < MB < GB < TB < PB (each is 1024 times the previous).
Q12. SSD vs HDD — key advantage of SSD?
A12. SSD uses flash memory with no moving parts, so it is faster, quieter and more shock-resistant than a magnetic HDD.